I'm sure you have tested it, but, as I understand the rules, you need one turn to take-off, another to enter orbit (as there's no other way to overcome gravity without it without overload, and merchant ships have not this capacity), another to move to Luna's gravity well, a fourth one to begin orbiting Luna, and another one to land, and that makes me 5 turns mínimum...
See that when moving from Terra gravity well to Luna's, the ship will not be in Luna orbit, regarless its vector, as rules say (page 4, Orbit):
quote:
A ship which moves at one hex per turn from one gravity hex to an adjacent gravity hex of the same body is in orbit
(bold is mine)
So, until it has so moved from one Luna's Gravity hex to another, it's not in Orbit, and cannot land, as rules specify (two paragraphs above last quote):
quote:
A ship may only land by expending on fuel point while in orbit
So, as Iunderstand it, you must first enter orbit (so going from one hex in its gravity well to another one also in its gravity well while at speed 1), and then land the next turn.
So, what did I undertand wrong?
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BTW, as an aside, I see a problem in the given example (PPT file), at the section turn 3 (with thrust):
It says that the ship cannot ignore the half gravity of Luna because it's the second gravity hex it enters, but rules don't say this:
quote:
Weak Gravity: (...)A ship passing through one weak gravity hex may ignore it or use it, as the player chooses. When two or more weak gravity hexes are entered consecutively, the second and latter hexes have the effect of full gravity hexes, regardless of how the first such hex is treated.
(Italics are original, bold is mine)
In the example, the ship does not move from one weak gravity hex to another, but from one full gravity hex to a weak gravity one, so it being the first weak gravity hex crossed, gravity could be ignored (or used, as player chooses)...
Is this example oficial (by the game authors) or yours?